Doyle Brunson Wins 10th Bracelet
"Established pros" are the new "Internet whiz-kids" at this year's WSOP.
And 10-3 is the new 10-2.
Doyle Brunson has won his 10th bracelet, tying Johnny Chan for the most all-time.
Brunson bested Minh Ly in Event #29 ($5,000 Short-Handed NLH) for the title. On the final hand, Minh Ly limped on the button, and Brunson attempted a steal by moving all in. Ly, setting a trap, quickly calls. Brunson has the 10c-3d... Ly the Ks-Qd. The flop produces a 9s-8d-3h, giving Brunson a pair. A King or Queen do not make an appearance on the turn and river, and Brunson wins the event and $367,800. Minh Ly takes home $203,715 for 2nd.
At 71, Brunson is having maybe one of the best year's of his career. He's a true class act, champion, and legend of the game.
Other cash finishers in Event #29 (making this win for Brunson even more impressive) includes: 3rd - Scotty Nguyen ($106,105), 4th - Layne Flack ($99,030), 5th - Ayaz Mahmood ($82,055), 6th - Jason Lester ($67,905), 7th - Steven Rosen ($45,270), 8th Men Nguyen ($45,270), 11th - Chris "Jesus" Ferguson ($16,975), 15th -John Hennigan ($11,320), 17th - John Juanda $11,320, 18th - Jean Michael Kabbaj ($11,320), 29th - Allen Cunningham ($8,490), 30th - Chip Reese ($8,490), 33rd - Peter Costa ($7,780), 40th - Lee Watkinson ($6,790).
The best part about this is that Helmuth now has two ahead him on the all-time list. cry...baby...cry!!!
Good luck in Vegas in WCP!
Posted by: Paul | July 01, 2005 at 12:57 PM
Love it.
Posted by: Slim | July 01, 2005 at 08:59 AM